Equilibrium Question 35
Question: The conjugate acid of $ HPO_3^{2-} $ is [EAMCET 1989]
Options:
A) $ H_3PO_4 $
B) $ H_3PO_3 $
C) $ H_2PO_3^{-} $
D) $ PO_4^{3-} $
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Answer:
Correct Answer: C
Solution:
$ \underset{\text{Conjugate acid}}{\mathop{H_2PO_4^{-}}}, $ ⇌ $ {H^{+}}+HPO{{_4^{2}}^{-}} $ action.