Equilibrium Question 35

Question: The conjugate acid of $ HPO_3^{2-} $ is [EAMCET 1989]

Options:

A) $ H_3PO_4 $

B) $ H_3PO_3 $

C) $ H_2PO_3^{-} $

D) $ PO_4^{3-} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \underset{\text{Conjugate acid}}{\mathop{H_2PO_4^{-}}}, $ ⇌ $ {H^{+}}+HPO{{_4^{2}}^{-}} $ action.



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