SATHEE: Equilibrium Question 327

Equilibrium Question 327

Question: What is the pH of a 1M $C H_{3} C O O H$ a solution $K_{a}$ of acetic acid $= 1.8 \times 10^{- 5} .$

$K = 10^{- 14} m o l^{2} l i t r e^{- 2}$ [DPMT 2002]

Options:

A) 9.4

B) 4.8

C) 3.6

D) 2.4

Show Answer

Answer:

Correct Answer: A

Solution:

$C H_{3} C O O^{-} + H_{2} O$ ⇌ $C H_{3} C O O H + O H^{-}$ \ $[O H^{-}] = c \times h; h = \sqrt{\frac{K_{w}}{K_{a}} \times c}$

$= \sqrt{\frac{10^{- 14}}{1.8 \times 10^{- 5}} \times 1}$

$= 2.35 \times 10^{- 5}$ \ $p O H = 4.62$ ; $p H = 9.38 \approx 9.4$

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