SATHEE: Equilibrium Question 305

Equilibrium Question 305

Question: For a weak acid $H A$ with dissociation constant $10^{- 9}, p O H$ of its 0.1 M solution is [CBSE PMT 1989]

Options:

A) 9

B) 3

C) 11

D) 10

Show Answer

Answer:

Correct Answer: D

Solution:

Dissociation constant of $H A = 10^{- 9}$

$H A$ ⇌ $H^{+} + A^{-}$

$[H^{+}] = \sqrt{\frac{K_{a}}{C}}$

$= \sqrt{\frac{10^{- 9}}{0.1}}$ ; $[H^{+}] = 10^{- 4}$

$∴, p H = 4$

$∵, p H + p O H = 14$

$p O H = 14 - p H$

$= 14 - 4$ ; $p O H = 10$

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Equilibrium Question 305

Question: For a weak acid HA with dissociation constant 10−9,pOH of its 0.1 M solution is [CBSE PMT 1989]

Options:

Answer:

Solution:

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Question: For a weak acid $H A$ with dissociation constant $10^{- 9}, p O H$ of its 0.1 M solution is [CBSE PMT 1989]