SATHEE: Equilibrium Question 295

Equilibrium Question 295

Question: Calculate the solubility of $A g C l$ (s) in $0.1, M, N a C l$ at $25^{\circ} C .,$

$K_{s p} (A g C l) = 2.8 \times 10^{- 10}$ [UPSEAT 2001]

Options:

A) $3.0 \times 10^{- 8} M L^{- 1}$

B) $2.5 \times 10^{- 7} M L^{- 1}$

C) $2.8 \times 10^{- 9} M L^{- 1}$

D) $2.5 \times 10^{7} M L^{- 1}$

Show Answer

Answer:

Correct Answer: C

Solution:

$\frac{2.8 \times 10^{- 10}}{0.1} = 2.8 \times 10^{- 9} M L^{- 1}$ .

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Equilibrium Question 295

Question: Calculate the solubility of AgCl (s) in 0.1,M,NaCl at 25∘C.,

Options:

Answer:

Solution:

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Question: Calculate the solubility of $A g C l$ (s) in $0.1, M, N a C l$ at $25^{\circ} C .,$