Equilibrium Question 295
Question: Calculate the solubility of $ AgCl $ (s) in $ 0.1,M,NaCl $ at $ 25{}^\circ C., $
$ K _{sp}(AgCl)=2.8\times {10^{-10}} $ [UPSEAT 2001]
Options:
A) $ 3.0\times {10^{-8}}M{L^{-1}} $
B) $ 2.5\times {10^{-7}}M{L^{-1}} $
C) $ 2.8\times {10^{-9}}M{L^{-1}} $
D) $ 2.5\times 10^{7}M{L^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{2.8\times {10^{-10}}}{0.1}=2.8\times {10^{-9}}M{L^{-1}} $ .
