SATHEE: Equilibrium Question 293

Equilibrium Question 293

Question: If the solubility products of $A g C l$ and $A g B r$ are $1.0 \times 10^{- 8}, M$ and $3.5 \times 10^{- 13}$ respectively, then the relation between the solubilities (denoted by the symbol $‘ S^{'}$ ) of these salts can correctly be represented as [MP PET 1994]

Options:

A) $S$ of $A g B r$ is less than that of $A g C l$

B) $S$ of ${(C H_{3})}_{3} C^{+}$ is greater than that of $A g C l$

C) $10^{- 11} M$ of $B O H + H^{+}$ is equal to that of $A g C l$

D) $S$ of $A g B r$ is $10^{6}$ times greater than that of $A g C l$

Show Answer

Answer:

Correct Answer: A

Solution:

AgCl $K_{s p} = 1.2 \times 10^{- 10}$

$S = \sqrt{1.2 \times 10^{- 10}}$ ; $S = 1.09 \times 10^{- 5}$ AgBr $K_{s p} = 3.5 \times 10^{- 13}$

$S = \sqrt{3.5 \times 10^{- 13}}$

$= 5.91 \times 10^{- 6}$ So that S of AgBr is less than that of AgCl.

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Equilibrium Question 293

Question: If the solubility products of AgCl and AgBr are 1.0×10−8,M and 3.5×10−13 respectively, then the relation between the solubilities (denoted by the symbol ‘S′ ) of these salts can correctly be represented as [MP PET 1994]

Options:

Answer:

Solution:

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Question: If the solubility products of $A g C l$ and $A g B r$ are $1.0 \times 10^{- 8}, M$ and $3.5 \times 10^{- 13}$ respectively, then the relation between the solubilities (denoted by the symbol $‘ S^{'}$ ) of these salts can correctly be represented as [MP PET 1994]