SATHEE: Equilibrium Question 284

Equilibrium Question 284

Question: $K_{s p}$ for $C r {(O H)}_{3}$ is $2.7 \times 10^{- 31}$ . What is its solubility in moles / litre. [JEE Orissa 2004]

Options:

A) $1 \times 10^{- 8}$

B) $8 \times 10^{- 8}$

C) $1.1 \times 10^{- 8}$

D) $0.18 \times 10^{- 8}$

Show Answer

Answer:

Correct Answer: A

Solution:

$C r {(O H)}_{3} \to \underset{x}{C r^{+ 3}}, + \underset{3 x}{3 O H^{-}},$

$K_{s p} = x . {(3 x)}^{3} = 27 x^{4}$

$x = \sqrt[4]{\frac{K_{s p}}{27}}$ ; $x = \sqrt[4]{\frac{2.7 \times 10^{- 31}}{27}}$

$x = 1 \times 10^{- 8}$ mole/litre.

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Equilibrium Question 284

Question: Ksp for Cr(OH)3 is 2.7×10−31 . What is its solubility in moles / litre. [JEE Orissa 2004]

Options:

Answer:

Solution:

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Question: $K_{s p}$ for $C r {(O H)}_{3}$ is $2.7 \times 10^{- 31}$ . What is its solubility in moles / litre. [JEE Orissa 2004]