SATHEE: Equilibrium Question 283

Equilibrium Question 283

Question: A 0.004 M solution of $N a_{2} S O_{4}$ is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of disociation of $N a_{2} S O_{4}$ is [IIT JEE Screening 2004]

Options:

A) 25%

B) 50%

C) 75%

D) 85%

Show Answer

Answer:

Correct Answer: C

Solution:

$\underset{(0.004 - x)}{N a_{2} S O_{4}},$ ⇌ $\underset{2 x}{2 N a^{+}}, + \underset{x}{S O_{4}^{2 -}},$ Since both the solution are isotonic $0.004 + 2 x = 0.01$

$∴ x = 3 \times 10^{- 3}$

$∴$ Percent dissociation $= \frac{3 \times 10^{- 3}}{0.004} \times 100 = 75$ .

Equilibrium Question 283

Question: A 0.004 M solution of $N a_{2} S O_{4}$ is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of disociation of $N a_{2} S O_{4}$ is [IIT JEE Screening 2004]

Options:

Answer:

Solution:

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Equilibrium Question 283

Question: A 0.004 M solution of Na2SO4 is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of disociation of Na2SO4 is [IIT JEE Screening 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A 0.004 M solution of $N a_{2} S O_{4}$ is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of disociation of $N a_{2} S O_{4}$ is [IIT JEE Screening 2004]