Equilibrium Question 283

Question: A 0.004 M solution of $ Na_2SO_4 $ is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of disociation of $ Na_2SO_4 $ is [IIT JEE Screening 2004]

Options:

A) 25%

B) 50%

C) 75%

D) 85%

Show Answer

Answer:

Correct Answer: C

Solution:

$ \underset{(0.004-x)}{\mathop{Na_2SO_4}}, $ ⇌ $ \underset{2x}{\mathop{2N{a^{+}}}},+\underset{x}{\mathop{SO_4^{2-}}}, $ Since both the solution are isotonic $ 0.004+2x=0.01 $

$ \therefore \ \ x=3\times {10^{-3}} $

$ \therefore \ \ $ Percent dissociation $ =\frac{3\times {10^{-3}}}{0.004}\times 100=75% $ .



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