Equilibrium Question 280

Question: What is [H+] of a solution that is 0.01,M in HCN and 0.02,M in NaCN

(Ka for HCN=6.2×1010) [MP PMT 2000]

Options:

A) 3.1×1010

B) 6.2×105

C) 6.2×1010

D) 3.1×1010

Show Answer

Answer:

Correct Answer: D

Solution:

Ka=[H+][CN][HCN]

6.2×1010=[H+][0.02][0.01]

[H+]=6.2×1010×0.010.02=3.1×1010



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