Equilibrium Question 271
Question: Self-ionisation of liquid ammonia occurs as, $ 2NH_3 $ ⇄ $ NH_4^{+}+NH_2^{-};,K={10^{-10}} $ . In this solvent, an acid might be [JIPMER 2001]
Options:
A) $ NH_4^{+} $
B) $ NH_3 $
C) Any species that will form $ NH_4^{+} $
D) All of these
Show Answer
Answer:
Correct Answer: A
Solution:
A substance which can donate a proton is known as acid so $ NH_4^{+} $ will be a acid.