Equilibrium Question 251
Question: If dissociation for reaction, $ PCl_5 $ ⇌ $ PCl_3+Cl_2 $ Is 20% at 1 atm. pressure. Calculate $ K_{c} $ [Kerala (Med.) 2003]
Options:
A) 0.04
B) 0.05
C) 0.07
D) 0.06
Show Answer
Answer:
Correct Answer: B
Solution:
$ K_{c}=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{[ \frac{20}{100} ]\times [ \frac{20}{100} ]}{[ \frac{80}{100} ]} $
$ =\frac{0.2\times 0.2}{0.8}=\frac{0.04}{0.8}=0.05 $