Equilibrium Question 242

Question: A saturated solution of $ Ag_2SO_4 $ is $ 2.5\times {10^{-2}} $ M; The value of its solubility product is [Pb.CET 2004]

Options:

A) $ 62.5\times {10^{-6}} $

B) $ 6.25\times {10^{-4}} $

C) $ 15.625\times {10^{-6}} $

D) $ 3.125\times {10^{-6}} $

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Answer:

Correct Answer: A

Solution:

For $ Ag_2SO_4\to \underset{2x}{\mathop{2A{g^{+}}}},+\underset{x}{\mathop{SO_4^{–}}}, $

$ K _{sp}={{(2x)}^{2}}.x $ ; $ K _{sp}=4x^{3} $ ; $ K _{sp}=4\times {{(2.5\times {10^{-2}})}^{3}} $

$ K _{sp}=62.5\times {10^{-6}} $



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