Equilibrium Question 237
Question: Hydrolysis constant for a salt of weak acid and weak base would be [RPMT 1999]
Options:
A) $ K_{h}=\frac{K_{w}}{K_{a}} $
B) $ K_{h}=\frac{K_{w}}{K_{b}} $
C) $ K_{h}=\frac{K_{w}}{K_{a}K_{b}} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ K_{h}=\frac{K_{w}}{K_{a}\times K_{b}} $