Equilibrium Question 237

Question: Hydrolysis constant for a salt of weak acid and weak base would be [RPMT 1999]

Options:

A) $ K_{h}=\frac{K_{w}}{K_{a}} $

B) $ K_{h}=\frac{K_{w}}{K_{b}} $

C) $ K_{h}=\frac{K_{w}}{K_{a}K_{b}} $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ K_{h}=\frac{K_{w}}{K_{a}\times K_{b}} $



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