SATHEE: Equilibrium Question 205

Equilibrium Question 205

Question: At 298 K, the solubility of $P b C l_{2}$ is $2 \times 10^{- 2} m o l / l i t$ , then $K_{s p} =$ [RPMT 2002]

Options:

A) $1 \times 10^{- 7}$

B) $3.2 \times 10^{- 7}$

C) $1 \times 10^{- 5}$

D) $3.2 \times 10^{- 5}$

Show Answer

Answer:

Correct Answer: D

Solution:

$P b C l_{2}$ ⇌ $\underset{(S)}{P b^{2 +}}, + \underset{{(2 S)}^{2}}{2 C l^{-}},$

$K_{s p} = 4 S^{3} = 4 \times {(2 \times 10^{- 2})}^{3} = 3.2 \times 10^{- 5}$

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