SATHEE: Equilibrium Question 164

Equilibrium Question 164

Question: What is the $p H$ value of $\frac{N}{1000}, K O H$ solution [CPMT 1975; MNR 1986, 91; Pb. CET 2004]

Options:

A) $10^{- 11}$

B) 3

C) 2

D) 11

Show Answer

Answer:

Correct Answer: D

Solution:

$10^{- 3} N$ KOH will give $[O H^{-}] = 10^{- 2}$ M $p O H = 2$

$∵, p H + p O H = 14$ , $p H = 14 - 2 = 12$

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Equilibrium Question 164

Question: What is the pH value of N1000,KOH solution [CPMT 1975; MNR 1986, 91; Pb. CET 2004]

Options:

Answer:

Solution:

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Question: What is the $p H$ value of $\frac{N}{1000}, K O H$ solution [CPMT 1975; MNR 1986, 91; Pb. CET 2004]