Equilibrium Question 149

Question: The solubility product of a salt having general formula $ MX_2, $ in water is: $ 4\times {10^{-12}} $ . The concentration of $ {M^{2+}} $ ions in the aqueous solution of the salt is [AIEEE 2005]

Options:

A) $ 2.0\times {10^{-6}}M $

B) $ 1.0\times {10^{-4}}M $

C) $ 1.6\times {10^{-4}}M $

D) $ 4.0\times {10^{-10}}M $

Show Answer

Answer:

Correct Answer: B

Solution:

$ MX_2 $ ⇌ $ \underset{S}{\mathop{{M^{2+}}}},+\underset{2S,}{\mathop{2{X^{-}}}}, $

$ K _{sp}={{(2S)}^{2}}(S)=4S^{3} $

Þ $ S=2\sqrt[3]{\frac{K _{sp}}{4}}=\sqrt[3]{\frac{4\times {10^{-12}}}{4}}=1.0\times {10^{-4}}M $ .



NCERT Chapter Video Solution

Dual Pane