SATHEE: Equilibrium Question 146

Equilibrium Question 146

Question: Calculate $Δ G^{\circ}$ for conversion of oxygen to ozone $3 / 2 O_{2} (g) \to O_{3} (g)$ at 298 K, if $K_{p}$ for this conversion is $2.47 \times 10^{- 29}$ [DPMT 2004]

Options:

A) $163 k J m o l^{- 1}$

B) $2.4 \times 10^{2} k J m o l^{- 1}$

C) $1.63 k J m o l^{- 1}$

D) $2.38 \times 10^{6} k J m o l^{- 1}$

Show Answer

Answer:

Correct Answer: A

Solution:

As we know that, $Δ G^{o} = - 2.303 R T, \log, K_{p}$ Therefore, $Δ G^{o} = - 2.303 \times (8.314) \times (298),$

$(\log, 2.47 \times 10^{- 29})$

$Δ G^{o} = 16, 3000, J, m o l^{- 1}$

$= 163, K J, m o l^{- 1}$

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Equilibrium Question 146

Question: Calculate ΔG∘ for conversion of oxygen to ozone 3/2 O2(g)→O3(g) at 298 K, if Kp for this conversion is 2.47×10−29 [DPMT 2004]

Options:

Answer:

Solution:

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Question: Calculate $Δ G^{\circ}$ for conversion of oxygen to ozone $3 / 2 O_{2} (g) \to O_{3} (g)$ at 298 K, if $K_{p}$ for this conversion is $2.47 \times 10^{- 29}$ [DPMT 2004]