Equilibrium Question 127
Question: Conjugate base of $ HBr $ is [MP PET/PMT 1988]
Options:
A) $ H_2B{r^{+}} $
B) $ {H^{+}} $
C) $ B{r^{-}} $
D) $ B{r^{+}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ HBr+H_2O $ ⇌ $ H_3{O^{+}}+B{r^{-}} $
A) $ H_2B{r^{+}} $
B) $ {H^{+}} $
C) $ B{r^{-}} $
D) $ B{r^{+}} $
Correct Answer: C
$ HBr+H_2O $ ⇌ $ H_3{O^{+}}+B{r^{-}} $
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