SATHEE: Equilibrium Question 107

Equilibrium Question 107

Question: Ammonia gas dissolves in water to form $N H_{4} O H$ . In this reaction water acts as [KCET (Engg./Med.) 1999]

Options:

A) A conjugate base

B) A non-polar solvent

C) An acid

D) A base

Show Answer

Answer:

Correct Answer: C

Solution:

$\underset{A c i d}{H_{2} O,}, + \underset{b a s e}{N H_{3}},$ ⇌ $N H_{4}^{+} + O H^{-}$ . In this reaction $H_{2} O$ acts as acid because it donate a proton.

Equilibrium Question 107

Question: Ammonia gas dissolves in water to form $N H_{4} O H$ . In this reaction water acts as [KCET (Engg./Med.) 1999]

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

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Other Resources

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Sample Mock Test

Mentorship

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Equilibrium Question 107

Question: Ammonia gas dissolves in water to form NH4OH . In this reaction water acts as [KCET (Engg./Med.) 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Ammonia gas dissolves in water to form $N H_{4} O H$ . In this reaction water acts as [KCET (Engg./Med.) 1999]