D-And F-Block Elements Ques 76

Question: What is the oxidation number of iron in the compound $

[Fe{{(H_2O)}_5}(NO)]SO_4 $ [Pb. CET 2001]

Options:

A) $ +2 $

B) $ +3 $

C) $ \pm 1 $

D) $ \pm 4 $

Show Answer

Answer:

Correct Answer: A

Solution:

Applying the oxidation number rule in $ [Fe{{(H_2O)}_5}(NO)]SO_4 $ ( $ \because $ $ H_2O $ and NO are neutral)

$ [x+(0)\times 5+0]+(-2)=0 $ $ x+0+0-2=0 $

Þ $ x=+2 $ Hence, oxidation number of Fe is +2.



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