A) $ Zn{{(OH)}_2} $
B) $ ZnCl_2 $
C) $ Na_2ZnO_2 $
D) $ Zn{{(OH)}_3} $
Correct Answer: C
$ ZnO+2NaOH,\to ,\underset{\text{Sodium zincate}}{\mathop{Na_2ZnO_2}},+H_2O $
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