D-And F-Block Elements Ques 443
Question: $ FeCr_2O_4 $ (chromite) is converted to Cr by following steps: Chromite $ \xrightarrow{I}Na_2CrO_4 $ $ \xrightarrow{II}Cr_2O_3\xrightarrow{III}Cr,, $ I, II and III are
Options:
A) I II III $ Na_2Co_3/air,\Delta $ C C
B) I II III $ NaOH/air,\Delta $ C, $ \Delta $ Al, $ \Delta $
C) I II III $ NaOH/air,\Delta $ C, $ \Delta $ Mg, $ \Delta $
D) I II III cone. $ H_2SO_4,\Delta $ $ NH_4Cl $ C, $ \Delta $
Show Answer
Answer:
Correct Answer: B
Solution:
$ FeCr_2O_4\xrightarrow[\Delta ]{NaOH/air}Na_2CrO_4\xrightarrow{C,\Delta }Cr_2O_3 $ $ \xrightarrow{A1,\Delta }Cr $
