A) $ CrO_2Cl_2 $
B) $ CrO_4^{2-} $
C) $ C{{r}^{3+}} $
D) $ C{{r}^{2+}} $
Correct Answer: C
$ Cr_2O_7^{2-}+8{{H}^{+}}+2SO_3^{2-},\to ,2C{{r}^{+3}}+3SO_4^{2-}+4H_2O $
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