[DPMT 2005]
A) Curium
B) Californium
C) Uranium
D) Terbium
Correct Answer: D
Terbium is lanthanide as it belongs to $ 4f- $ series having configuration $ [Xe]4s^{9}6s^{2} $ .
However the remaining members belong to $ 5f- $ series (actinides).
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