SATHEE: Co-Ordination Compounds Question 96

Co-Ordination Compounds Question 96

Question: Hybridization of Fe in $K_{3} F e {(C N)}_{6}$ is

[DCE 2002]

Options:

A) $s p^{3}$

B) $d s p^{3}$

C) $s p^{3} d^{2}$

D) $d^{2} s p^{3}$

Show Answer

Answer:

Correct Answer: D

Solution:

$K_{3} [F e {(C N)}_{6}]$ Electronic configuration of $F e = [A r] 4 s^{2} 3 d^{6}$ Electronic configuration of $F e^{+ 3} = [A r] 3 d^{5}$ Number of ligand (coordination numbr)=6 Nature of ligand is strong field.

Hybridization of $F e$ is $d^{2} s p^{3}$ .

Co-Ordination Compounds Question 96

Question: Hybridization of Fe in $K_{3} F e {(C N)}_{6}$ is

Options:

Answer:

Solution:

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Co-Ordination Compounds Question 96

Question: Hybridization of Fe in K3Fe(CN)6 is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Hybridization of Fe in $K_{3} F e {(C N)}_{6}$ is