Co-Ordination Compounds Question 90

Question: The shape of $ {{[ Cu{{( NH_3 )}_4} ]}^{2+}} $ is square planar, $ C{u^{2+}} $ in this complex is

[NCERT 1989; RPET 1999]

Options:

A) $ sp^{3} $ hybridised

B) $ dsp^{2} $ hybridised

C) $ sp^{3}d $ hybridised

D) $ sp^{3}d^{2} $ hybridized

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Answer:

Correct Answer: B

Solution:

Due to formation of inner orbital complex.



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