Co-Ordination Compounds Question 64
Question: The coordination number and oxidation state of $ Cr $ in $ K_3
[ Cr{{( C_2O_4 )}_3} ] $ are, respectively [CBSE PMT 1995]
Options:
A) 4 and +2
B) 6 and +3
C) 3 and +3
D) 3 and 0
Show Answer
Answer:
Correct Answer: B
Solution:
Its coordination number will be 6 because it is bonded with three bidentale ligands.
Oxi. No.of $ Cr $ in $ \underset{-1}{\mathop{K_3}},[Cr\underset{-2}{\mathop{{{(C_2O_4)} _3}}},] $ is $ x+3(-2)+3(+1)=0 $
$ \Rightarrow x=+3 $
