Co-Ordination Compounds Question 60

Question: Silver chloride dissolves in excess of $ NH_4OH $ . The cation present in this solution is

[EAMCET 1998]

Options:

A) $ A{g^{+}} $

B) $ {{[ Ag{{( NH_3 )}_2} ]}^{+}} $

C) $ {{[ Ag{{( NH_3 )}_4} ]}^{+}} $

D) $ {{[ Ag{{( NH_3 )}_6} ]}^{+}} $

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Answer:

Correct Answer: B

Solution:

$ \underset{[Ag{{(NH_3)}_2}]+C{l^{-}}}{\mathop{\underset{{}}{\mathop{AgCl+2NH_4OH\to [Ag,{{(NH_3)}_2}],}},Cl+2H_2O}}, $



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