SATHEE: Co-Ordination Compounds Question 60

Co-Ordination Compounds Question 60

Question: Silver chloride dissolves in excess of $N H_{4} O H$ . The cation present in this solution is

[EAMCET 1998]

Options:

A) $A g^{+}$

B) ${[A g {(N H_{3})}_{2}]}^{+}$

C) ${[A g {(N H_{3})}_{4}]}^{+}$

D) ${[A g {(N H_{3})}_{6}]}^{+}$

Show Answer

Answer:

Correct Answer: B

Solution:

$\underset{[A g {(N H_{3})}_{2}] + C l^{-}}{\underset{}{A g C l + 2 N H_{4} O H \to [A g, {(N H_{3})}_{2}],}, C l + 2 H_{2} O},$

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