Co-Ordination Compounds Question 57

Question: Prussian blue is formed when

[CBSE PMT 1990]

Options:

A) Ferrous sulphate reacts with $ FeCl_3 $

B) Ferric sulphate reacts with $ K_4[ Fe{{(CN)}_6} ] $

C) Ferrous ammonium sulphate reacts with $ FeCl_3 $

D) Ammonium sulphate reacts with $ FeCl_3 $

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Answer:

Correct Answer: B

Solution:

$ Fe_2,{{(SO_4)}_3}\to 2F{e^{3+}}+3SO_4^{2-} $

$ K_4[Fe{{(CN)}_6}]+2F{e^{3+}}\to \underset{Prussion,blue}{\mathop{Fe_4{{[Fe{{(CN)}_6}]}_3}}}, $ .



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