SATHEE: Co-Ordination Compounds Question 57

Co-Ordination Compounds Question 57

Question: Prussian blue is formed when

[CBSE PMT 1990]

Options:

A) Ferrous sulphate reacts with $F e C l_{3}$

B) Ferric sulphate reacts with $K_{4} [F e {(C N)}_{6}]$

C) Ferrous ammonium sulphate reacts with $F e C l_{3}$

D) Ammonium sulphate reacts with $F e C l_{3}$

Show Answer

Answer:

Correct Answer: B

Solution:

$F e_{2}, {(S O_{4})}_{3} \to 2 F e^{3 +} + 3 S O_{4}^{2 -}$

$K_{4} [F e {(C N)}_{6}] + 2 F e^{3 +} \to \underset{P r u s s i o n, b l u e}{F e_{4} {[F e {(C N)}_{6}]}_{3}},$ .

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