Co-Ordination Compounds Question 57
Question: Prussian blue is formed when
[CBSE PMT 1990]
Options:
A) Ferrous sulphate reacts with $ FeCl_3 $
B) Ferric sulphate reacts with $ K_4[ Fe{{(CN)}_6} ] $
C) Ferrous ammonium sulphate reacts with $ FeCl_3 $
D) Ammonium sulphate reacts with $ FeCl_3 $
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Answer:
Correct Answer: B
Solution:
$ Fe_2,{{(SO_4)}_3}\to 2F{e^{3+}}+3SO_4^{2-} $
$ K_4[Fe{{(CN)}_6}]+2F{e^{3+}}\to \underset{Prussion,blue}{\mathop{Fe_4{{[Fe{{(CN)}_6}]}_3}}}, $ .