Co-Ordination Compounds Question 48
Question: The formula of alum is
[Pb. CET 2002]
Options:
A) $ K_2SO_4.Al_2{{(SO_4)}_3}.24H_2O $
B) $ K_4[Fe{{(CN)}_6}] $
C) $ K_2SO_4.Al_2{{(SO_4)}_3}.6H_2O $
D) $ Na_2CO_3.10H_2O $
Show Answer
Answer:
Correct Answer: A
Solution:
General formula for alum is $ M_2SO_4.R_2{{(SO_4)}_3}.24H_2O $
$ M= $ mono valent cation $ ({K^{+}},,N{a^{+}}….) $
$ R= $ Trivalent cation $ (A{l^{+3}},,F{e^{+3}}) $ Hence, $ K_2SO_4Al_2{{(SO_4)}_2}.24H_2O $ represent an alum.
