[CBSE PMT 1994]
A) $ Br $
B) $ C_2O_4^{2-} $
C) $ CH_3NH_2 $
D) $ CH_3C\equiv N $
Correct Answer: B
$ C_2O_4^{2-} $ (oxalate ion) has two donor O atoms and hence is a bidentate ligand.
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