Co-Ordination Compounds Question 38
Question: In $ K_4Fe{{( CN )}_6}, $ $ Fe $ is in the form of
Options:
A) An atom
B) An ion
C) Cationic complex
D) Anionic complex
Show Answer
Answer:
Correct Answer: D
Solution:
$ K_4[Fe,{{(CN)}_6}]\to 4{K^{+}}+{{[Fe,{{(CN)}_6}]}^{4-}} $ Complex has negative charge so it is anionic complex.