Co-Ordination Compounds Question 38

Question: In $ K_4Fe{{( CN )}_6}, $ $ Fe $ is in the form of

Options:

A) An atom

B) An ion

C) Cationic complex

D) Anionic complex

Show Answer

Answer:

Correct Answer: D

Solution:

$ K_4[Fe,{{(CN)}_6}]\to 4{K^{+}}+{{[Fe,{{(CN)}_6}]}^{4-}} $ Complex has negative charge so it is anionic complex.



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