A) $ Hg_2I_2 $
B) $ {{[HgI_3]}^{-}} $
C) $ {{[HgI_4]}^{2-}} $
D) none of these
Correct Answer: C
$ HgI_2(s)+2{I^{-}}(aq)\to {{[HgI_4]}^{2-}}(aq) $
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