Co-Ordination Compounds Question 289
Question: $ [Cr{{(H_2O)}_6}]Cl_3 $ (atomic number of $ Cr=24 $ ) has a magnetic moment of 3.83 BM. The correct distribution of 3d-elections in the chromium present in the complex is
Options:
A) $ 3d_xy^{1},3d_yz^{1},3d_zx^{1} $
B) $ 3d_xy^{1},3d_yz^{1},3d_{z^{2}}^{1} $
C) $ 3d_{(x^{2}-y^{2})}^{1},3d_{z^{2}}^{1},3d_zx^{1} $
D) $ 3d_xy^{1},3d_{(x^{2}-y^{2})}^{1},3d_xz^{1} $
Show Answer
Answer:
Correct Answer: A
Solution:
Magnetic moment indicates that there are three unpaired electrons present in chromium.
These must be present in lower energy orbitals which are $ 3d_{xy},3d_{yz} $ and $ 3d_{xz} $ .
