SATHEE: Co-Ordination Compounds Question 279

Co-Ordination Compounds Question 279

Question: In the complexes ${[F e {(H_{2} O)}_{6}]}^{3 +}, {[F e {(C N)}_{6}]}^{3 -}$ , ${[F e {(C_{2} O_{4})}_{3}]}^{3 -}$ and ${[F e C l_{6}]}^{3 -}$ , more stability is shown by

Options:

A) ${[F e {(H_{2} O)}_{6}]}^{3 +}$

B) ${[F e {(C N)}_{6}]}^{3 -}$

C) ${[F e {(C_{2} O_{4})}_{3}]}^{3 -}$

D) ${[F e C l_{6}]}^{3 -}$

Show Answer

Answer:

Correct Answer: C

Solution:

${[F e {(C_{2} O_{4})}_{3}]}^{3 -}$ .

The iron is present in the highest oxidation state $F e^{3 +}$ and $C_{2} O {_{4}^{2 -}}^{}$ is a chelating ligand.

Chelates are always form more stable complexes

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Co-Ordination Compounds Question 279

Question: In the complexes [Fe(H2O)6]3+,[Fe(CN)6]3− , [Fe(C2O4)3]3− and [FeCl6]3− , more stability is shown by

Options:

Answer:

Solution:

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Question: In the complexes ${[F e {(H_{2} O)}_{6}]}^{3 +}, {[F e {(C N)}_{6}]}^{3 -}$ , ${[F e {(C_{2} O_{4})}_{3}]}^{3 -}$ and ${[F e C l_{6}]}^{3 -}$ , more stability is shown by