Co-Ordination Compounds Question 271

Question: The magnetic moment of the complex anion [Cr(NO)(NH3)(CN)4]2 is:

Options:

A) 5.91 BM

B) 3.87 BM

C) 1.73 BM

D) 2.82 BM

Show Answer

Answer:

Correct Answer: D

Solution:

In [Cr(NO)(NH3)(CN)4]2,

Cr2+(d4) is given as: i.e., 2 unpaired electrons μ=2(2+2)=8=2.82,BM



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