Co-Ordination Compounds Question 235

Question: The pair in which both species have same magnetic moment (spin only value) is

Options:

A) $ {{[Cr{{(H_2O)}_6}]}^{2+}},{{[CoCl_4]}^{2-}} $

B) $ {{[Cr{{(H_2O)}_6}]}^{2+}},{{[Fe{{(H_2O)}_6}]}^{2+}} $

C) $ {{[Mn{{(H_2O)}_6}]}^{2+}},{{[Cr{{(H_2O)}_6}]}^{2+}} $

D) $ {{[CoCl_4]}^{2-}},{{[Fe{{(H_2O)}_6}]}^{2+}} $

Show Answer

Answer:

Correct Answer: B

Solution:

Same magnetic moment = Same number of unpaired electrons.

$ \mu =\sqrt{n(n+2)} $ where n = number of unpaired electrons $ C{o^{2+}}=3d^{7},3 $ unpaired electrons; $ C{r^{2+}}=3d^{4},4 $ unpaired electrons; $ M{n^{2+}}=3d^{5},5 $ unpaired electrons; $ F{e^{2+}}=3d^{6},4 $ unpaired electrons.



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