Co-Ordination Compounds Question 227
Question: What is the magnetic moment (spin only) and hybridisation of the brown ring complex $ [ Fe{{( H_2O )}_5}NO ]SO_4 $ ?
Options:
A) $ \sqrt{3}BM,sp^{3}d^{2} $
B) $ \sqrt{3}BM,d^{2}sp^{3} $
C) $ \sqrt{15}BM,sp^{3}d^{2} $
D) $ \sqrt{15}BM,d^{2}sp^{3} $
Show Answer
Answer:
Correct Answer: C
Solution:
Number of unpaired electrons = 3 $ {\mu_{eff}}=3.9BM $ type of hybridisation $ =sp^{3}d^{2} $
