Co-Ordination Compounds Question 222
Question: Which of the following will give maximum number of isomers?
Options:
A) $ [Co{{(NH_3)}_4}Cl_2] $
B) $ {{[Ni(en){{(NH_3)}_4}]}^{2+}} $
C) $ [Ni{{(C_2O_4)}_4}{{(en)}_2}] $
D) $ {{[Cr{{(SCN)}_2}{{(NH_3)}_4}]}^{2+}} $
Show Answer
Answer:
Correct Answer: D
Solution:
The complex ion $ {{[Cr{{(SCN)}_2}{{(NH_3)}_4}]}^{2+}} $ can exhibit geometrical and linkage isomerism
