Co-Ordination Compounds Question 167

Question: Match List I (complex ions) with List II (CFSE) and select the correct answer using the codes given below the list;
List I List II
(P) $ {{[Mn(H_2O_6)]}^{2+}} $ 1. $ - $ 0.6 $ {\Delta_0} $
(Q) $ {{[Cr(H_2O_6)]}^{2+}} $ 2. $ - $ 0.4 $ {\Delta_0} $
(R) $ {{[Fe(H_2O_6)]}^{2+}} $ 3. 0
(S) $ {{[Cr(H_2O_6)]}^{3+}} $ 4. $ - $ 1.2 $ {\Delta_0} $

Code:

Options:

A) P $ \to $ 3, Q $ \to $ 1, R $ \to $ 2, S $ \to $ 4

B) P $ \to $ 1, Q $ \to $ 2, R $ \to $ 3, S $ \to $ 4

C) P $ \to $ 4, Q $ \to $ 3, R $ \to $ 2, S $ \to $ 1

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ CFSE=(-0.4x+0.6y) $

$ {\Delta_0}+2P $ $ PM{n^{2+}} $ $ d^{5} $ $ t_2g^{3}e_g^{2} $ 0 $ QC{r^{2+}} $

$ d^{4} $ $ t_2g^{3}e_g^{1} $ $ -0.6{\Delta_0} $ $ RF{e^{2+}} $ $ d^{6} $ $ t_2g^{4}e_g^{2} $ $ -0.4{\Delta_0} $ $ SC{r^{3+}} $ $ d^{3} $ $ t_2g^{3}e_g^{0} $ $ -0.2{\Delta_0} $



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