Co-Ordination Compounds Question 162

Question: Amongst Ni(CO)4,[Ni(CN)4]2 and NiCl42

Options:

A) Ni(CO)4 and NiCl42 are diamagnetic and [Ni(CN)4]2 is paramagnetic

B) [Ni(CN)4]2 and [Ni(CN)4]2 are diamagnetic and Ni(CO)4 is paramagnetic

C) Ni(CO)4 and [Ni(CN)4]2 are diamagnetic and NiCl42 is paramagnetic

D) Ni(CO)4 is diamagne and NiCl42 and [Ni(CN)4]2 are paramagnetic

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Answer:

Correct Answer: C

Solution:

[Ni(CO)4]: Oxidation state of Ni is 0 Ni=(Z=28)3d84s2 Co is a strong field ligand, it causes pairing. sp3 -Hybridisation (tetrahedral) There are no unpaired electrons, so the complex is diamagnetic.

Spin magnetic moment = Zero. [NiCl4]2: Ni2+=3d8 Cyano is a strong field ligand, it causes pairing. dsp2 -hybridsation (square planar) There are no unpaired electrons so, the complex is diamagnetic.

Spin magnetic moment = zero. [NiCl4]2: Ni2+=3d8 . Chloride is a weak field ligand, no pairing. sp3 -hybridisation (tetrahedral) There are two unpaired electrons, so the complex is paramagnetic. Spin magnetic moment μ=n(n+2)BM=2(2+2)BM=8BM



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