[RPMT 1997]
A) $ Ni{{(CO)}_4} $
B) $ Ni{{(Cl_4)}^{2-}} $
C) $ Ni(Br)_4^{2-} $
D) $ NiCl_2.4H_2O $
Correct Answer: A
$ CO $ is a strong ligand so induce pairing of electrons and hence $ Ni{{(CO)}_4} $ is diamagnetic.
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