SATHEE: Co-Ordination Compounds Question 125

Co-Ordination Compounds Question 125

Question: The total number of possible isomers for the complex compound $[C u^{I I} {(N H_{3})}_{4}], [P t^{I I} C l_{4}]$ are

[CBSE PMT 1998; DPMT 2004; J & K CET 2005]

Options:

A) 3

B) 4

C) 5

D) 6

Show Answer

Answer:

Correct Answer: D

Solution:

$[C u, {(N H_{3})}_{4}], ., [P t, C l_{4}]$ 2.

$[C u, {(N H_{3})}_{3} C l], ., [P t, C l_{3} (N H_{3})]$ 3.

$[C u, {(N H_{3})}_{2} C l_{2}] . [P t, C l_{2} {(N H_{3})}_{2}], c i s$ 4.

$[C u, {(N H_{3})}_{2} C l_{2}] . [P t, C l_{2} {(N H_{3})}_{2}], T r a n s$ 5.

$[C u, (N H_{3}) C l_{3}] . [P t (C l) {(N H_{3})}_{3}]$ 6.

$[, P t, {(N H_{3})}_{4} C l,], ., [C u, C l_{4}]$

Co-Ordination Compounds Question 125

Question: The total number of possible isomers for the complex compound $[C u^{I I} {(N H_{3})}_{4}], [P t^{I I} C l_{4}]$ are

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Co-Ordination Compounds Question 125

Question: The total number of possible isomers for the complex compound [CuII(NH3)4],[PtIICl4] are

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The total number of possible isomers for the complex compound $[C u^{I I} {(N H_{3})}_{4}], [P t^{I I} C l_{4}]$ are