SATHEE: Co-Ordination Compounds Question 116

Co-Ordination Compounds Question 116

Question: Amongst $N i {(C O)}_{4},$ ${[N i {(C N)}_{4}]}^{2 -}$ and ${[N i C l_{4}]}^{2 -}$

[IIT 1991]

Options:

A) $N i {(C O)}_{4}$ and ${[N i C l_{4}]}^{2 -}$ are diamagnetic and ${[N i {(C N)}_{4}]}^{2 -}$ is paramagnetic

B) ${[N i C l_{4}]}^{2 -}$ and ${[N i {(C N)}_{4}]}^{2 -}$ are diamagnetic and $N i {(C O)}_{4}$ is paramagnetic

C) $N i {(C O)}_{4}$ and ${[N i {(C N)}_{4}]}^{2 -}$ are diamagnetic and ${[N i C l_{4}]}^{2 -}$ is paramagnetic

D) $N i {(C O)}_{4}$ is diamagnetic and ${[N i C l_{4}]}^{2 -}$ and ${[N i {(C N)}_{4}]}^{2 -}$ are paramagnetic

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Answer:

Correct Answer: C

Solution:

The electronic configuration of Ni in ${[N i {(C N)}_{4}]}^{2 -},, {[N i (C l_{4})]}^{2 -}$ and $N i {(C O)}_{4}$ are as following $N i^{+}$ in ${[N i {(C N)}_{4}]}^{2 -}$ - $N i^{2 +}$ in ${[N i (C l_{4})]}^{2 -}$ - $N i$ in $[N i {(C O)}_{4}]$ - CO and $C N^{-}$ are strong ligands so they induces pairing of electrons so their complexes are diamagnetic while $C l^{-}$ is a weak ligand so it does not induce the pairing of electrons so its complex is paramagnetic.

Co-Ordination Compounds Question 116

Question: Amongst $N i {(C O)}_{4},$ ${[N i {(C N)}_{4}]}^{2 -}$ and ${[N i C l_{4}]}^{2 -}$

Options:

Answer:

Solution:

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Co-Ordination Compounds Question 116

Question: Amongst Ni(CO)4, [Ni(CN)4]2− and [NiCl4]2−

Options:

Answer:

Solution:

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Question: Amongst $N i {(C O)}_{4},$ ${[N i {(C N)}_{4}]}^{2 -}$ and ${[N i C l_{4}]}^{2 -}$