Classification Of Elements And Periodicity In Properties Ques 294
Question: $ N_0/2 $ atoms of X(g) are converted into $ {{X}^{+}}(g) $ by energy E. $ N_0/2 $ atoms of X(g) are converted into $ {{X}^{-}}(g) $ by energy $ E_2 $ . Hence, ionization potential and electron affinity of X(g) are
Options:
A) $ \frac{2E_1}{N_0},\frac{2(E_1-E_2)}{N_0} $
B) $ \frac{2E_1}{N_0},\frac{2E_2}{N_0} $
C) $ \frac{(E_1-E_2)}{N_0},\frac{2E_2}{N_0} $
D) None is correct
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ X(g)\xrightarrow[{}]{{}}{{X}^{+}}(g)+{{e}^{-}} $ If I is ionisation energy, then
$ \therefore $
$ \frac{N_0}{2}(I)=E_1 $
$ \therefore $
$ I=\frac{2E_1}{N_0} $ If E is electron affinity, then $ X(g)+{{e}^{-}}\xrightarrow[{}]{{}}{{X}^{-}}(g) $ $ \frac{N_0}{2}(E)=E_2 $
$ \therefore $
$ E=\frac{2E_2}{N_0} $
