Classification Of Elements And Periodicity In Properties Ques 28
Question: The order of magnitude of ionic radii of ions $ N{{a}^{+}},M{{g}^{2+}},A{{l}^{3+}} $ and $ S{{i}^{4+}} $ is [MP PMT 1996]
Options:
A) $ N{{a}^{+}}<M{{g}^{2+}}<A{{l}^{3+}}<S{{i}^{4+}} $
B) $ M{{g}^{2+}}>N{{a}^{+}}>A{{l}^{3+}}>S{{i}^{4+}} $
C) $ A{{l}^{3+}}>N{{a}^{+}}>S{{i}^{4+}}>M{{g}^{2+}} $
D) $ N{{a}^{+}}>M{{g}^{2+}}>A{{l}^{3+}}>S{{i}^{4+}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ N{{a}^{+}}>M{{g}^{2+}}>A{{l}^{3+}}>S{{i}^{4+}} $ . All are isoelectronic but nuclear charge per electron is greatest for $ S{{i}^{4+}} $ . So it has smallest size and nuclear charge per electron for $ N{{a}^{+}} $ is smallest. So it has largest size.
