Chemical Thermodynamics Question 48
Question: $ \underset{S^{o}(298,K),{{K}^{-1}}mo{{l}^{-1}}}{\mathop{{{H}^{+}}(aq)}},+\underset{-10.7}{\mathop{O{{H}^{-}}(aq)}},\xrightarrow{{}}\underset{+70}{\mathop{H_2O(l)}}, $ Standard entropy change for the above reaction is [DPMT 2004]
Options:
A) $ 60.3,J{{K}^{-1}}mo{{l}^{-1}} $
B) $ 80.7,J{{K}^{-1}}mo{{l}^{-1}} $
C) $ -70,J{{K}^{-1}}mo{{l}^{-1}} $
D) $ +10.7,J{{K}^{-1}}mo{{l}^{-1}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \underset{S^{o}(298K){K^{-}}mo{l^{-1}}}{\mathop{H^{+} _{(aq)}}},+\underset{-10.7}{\mathop{OH^{-} _{(aq)}}},\to \underset{+70}{\mathop{H_2O _{(l)}}}, $
$ \Delta S^{o}(298K)=\Delta S_{P}-\Delta S_{R} $
$ =70-(-10.7+0) $
$ 80.7,J{{K}^{-1}},mo{{l}^{-1}} $
