Chemical Thermodynamics Question 463
Question: Heat of neutralisation for the given reaction $ NaOH+HCl\to NaCl+H_2O $ is $ 57.1,kJ,mo{{l}^{-1}} $ . What will be the heat released when $ 0.25,mole $ of $ NaOH $ is titrated against $ 0.25,mole $ of $ HCl $
Options:
A) $ 22.5,kJ,mo{{l}^{-1}} $
B) $ 57.1,kJ,mo{{l}^{-1}} $
C) $ 14.3,kJ,mo{{l}^{-1}} $
D) $ 28.6,kJ,mo{{l}^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
- $ 57.1\times 0.25=14.3 $
$ kJ,mo{{l}^{-1}} $ .
