Chemical Thermodynamics Question 438

Question: For a carnot engine, the source is at 500K and the sink at 300K . What is efficiency of this engine

Options:

A) 0.2

B) 0.4

C) 0.6

D) 0.3

Show Answer

Answer:

Correct Answer: B

Solution:

  • Given that T1=500K,T2=300K

By using η=T1T2T1

=500300500=200500=0.4 .



NCERT Chapter Video Solution

Dual Pane