SATHEE: Chemical Thermodynamics Question 422

Chemical Thermodynamics Question 422

Question: Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are $- 382.64 k J m o l^{- 1}$ and $- 45.6 J K^{- 1} m o l^{- 1}$ , respectively Standard Gibb’s energy change for the same reaction at 298 K is

Options:

A) $- 22.1, k J, m o l^{- 1}$

B) $- 339.3 k J m o l^{- 1}$

C) $- 439.3 k J, m o l^{- 1}$

D) $- 523.2 k J m o l^{- 1}$

Show Answer

Answer:

Correct Answer: B

Solution:

$Δ G = Δ H - T Δ S$

$= - 382.64 - (298 \times 145.6 \times 10^{- 3})$

$= - 339.3 k J, m o l^{- 1}$

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Chemical Thermodynamics Question 422

Question: Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are −382.64kJmol−1 and −45.6JK−1mol−1 , respectively Standard Gibb’s energy change for the same reaction at 298 K is

Options:

Answer:

Solution:

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Question: Standard enthalpy and standard entropy changes for the oxidation of ammonia at 298 K are $- 382.64 k J m o l^{- 1}$ and $- 45.6 J K^{- 1} m o l^{- 1}$ , respectively Standard Gibb’s energy change for the same reaction at 298 K is