Chemical Thermodynamics Question 413
Question: The heats of neutralisation of $ CH_3COOH $ , $ HCOOH,HCN $ and $ H_2S $ are $ -13.2,-13.4 $ , $ ~-2.9 $ and $ -3.8kcal $ per equivalent respectively. Arrange the acids in increasing order of strength
Options:
A) $ HCOOH>CH_3COOH>H_2S>HCN $
B) $ CH_3COOH>HCOOH>H_2S>HCN $
C) $ H_2S>HCOOH>CH_3COOH>HCN $
D) $ HCOOH>H_2S>CH_3COOH>HCN $
Show Answer
Answer:
Correct Answer: A
Solution:
- The greater the (negative value) of heat of neutralisation, the more is the strength of the acid. Hence, $ HCOOH>CH_3COOH>H_2S>HCN $
